4x^2-48x-52=0

Solution for 4x^2-48x-52=0 equation:

4x^2-48x-52=0

a = 4; b = -48; c = -52;
Δ = b2-4ac
Δ = -482-4·4·(-52)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-56}{2*4}=\frac{-8}{8}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+56}{2*4}=\frac{104}{8}
=13
$